Problem: F6-6 (R.C. Hibbeler.)
Express the shear and moment functions in terms of x, and then draw the shear and moment diagrams for the simply supported beam.
Solution:
Check the other problems’ solutions for the same book here:
Solved Problems of Mechanics of Materials by R C Hibbeler – Book Solutions
As per the static equilibrium, ∑M=0, hence, RB*6 = 50 – 20 => RB = 5 kN
Also, ∑Fy = 0, hence the end support reactions are: Vertical Reactions, RA = -5.0 kN, and RB = 5.0 kN
Shear at x from the left support, Vx = -5 kN
Moment at x from the left support, Mx = 50 + RA*x or Mx = 50 – 5*x
